A particle is executing simple harmonic motio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In simple harmonic motion $(SHM)$,the particle oscillates between the extreme positions $+A$ and $-A$.One complete time period $T$ corresponds to

Vedclass · Accepted Answer

$2\,A$

Vedclass · Answer

(C) In simple harmonic motion $(SHM)$,the particle oscillates between the extreme positions $+A$ and $-A$.One complete time period $T$ corresponds to the particle moving from $+A$ to $-A$ and back to $+A$.In half a time period $(T/2)$,the particle moves from one extreme position to the other extreme position.For example,if the particle starts at $+A$,after time $T/2$,it will reach $-A$.The distance travelled is the total path length covered,which is $|+A - (-A)| = 2A$.

$A$ particle is executing simple harmonic motion with an amplitude $A$. The distance travelled by the particle in half time period is

Similar Questions

The equation of a particle executing $SHM$ is given by $x = 3 \cos(\frac{\pi}{2}t)$ cm,where $t$ is in seconds. The distance travelled by the particle in the first $8.5$ seconds is:

If displacement $x$ and velocity $v$ are related as $4v^2 = 25 - x^2$ in a $SHM$. Then the time period of the given $SHM$ is (Consider $SI$ units).

Which of the following is a necessary and sufficient condition for $S.H.M.$?

Explain periodic function.

For particle $P$ revolving around the centre $O$ with radius of circular path $r$ and angular velocity $\omega$,as shown in the figure,the projection of $OP$ on the $x$-axis at time $t$ is .................

Vedclass Test Series

Exam Paper Generator

Online Exam Module