$A$ particle is executing simple harmonic motion with an amplitude of $0.02 \ m$ and frequency $50 \ Hz$. The maximum acceleration of the particle is

$A$ point mass oscillates along the $x$-axis according to the law $x=x_0 \cos(\omega t - \frac{\pi}{4})$. If the acceleration of the particle is written as $a=A \cos(\omega t + \delta)$,then:

$A$ $0.10\, kg$ block oscillates back and forth along a horizontal surface. Its displacement from the origin is given by: $x = (10\,cm)\cos [(10\,rad/s)\,t + \pi /2\,rad]$. What is the maximum acceleration experienced by the block?

$A$ book is resting on a shelf that is undergoing vertical simple harmonic oscillations with an amplitude of $2.5 \,cm$. What is the minimum frequency of oscillation of the shelf for which the book will lose contact with the shelf (in $,Hz$)? (Assume that $g = 10 \,m/s^2$)

The magnitude of maximum acceleration is $\pi$ times that of maximum velocity of a simple harmonic oscillator. The time period of the oscillator in seconds is

$A$ body of mass $0.4 \text{ kg}$ performs simple harmonic motion. It experiences a restoring force of $0.4 \text{ N}$ when its displacement from the mean position is $4 \text{ cm}$. The force constant and magnitude of acceleration respectively are