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Question

(A) Let the side length of the regular hexagon be $a$. The particle moves with constant speed $v$.For motion from $A$ to $F$,the displacement is the v

Vedclass · Accepted Answer

$v/5$

Vedclass · Answer

(A) Let the side length of the regular hexagon be $a$. The particle moves with constant speed $v$.For motion from $A$ to $F$,the displacement is the vector $\vec{AF}$. Since $ABCDEF$ is a regular hexagon,the distance $AF$ is equal to the side length $a$.The time taken to travel from $A$ to $F$ along the path $A 	o B 	o C 	o D 	o E 	o F$ is $t = \frac{5a}{v}$.The magnitude of average velocity is given by $|\vec{v}_{av}| = \frac{|	ext{displacement}|}{	ext{time taken}}$.$|\vec{v}_{av}| = \frac{a}{5a/v} = \frac{v}{5}$.

$A$ particle moves with constant speed $v$ along a regular hexagon $ABCDEF$ in the same order. What is the magnitude of the average velocity for its motion from $A$ to $F$?

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