A particle of mass 0.3 , kg is subjected to a | vedclass

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(B) Given: Mass $m = 0.3 \, kg$,force constant $k = 15 \, N/m$,and displacement $x = 20 \, cm = 0.2 \, m$.According to Hooke's Law,the magnitude of th

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$10$

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(B) Given: Mass $m = 0.3 \, kg$,force constant $k = 15 \, N/m$,and displacement $x = 20 \, cm = 0.2 \, m$.According to Hooke's Law,the magnitude of the force is $F = kx$.Substituting the values: $F = 15 	imes 0.2 = 3 \, N$.Using Newton's Second Law,$F = ma$,the acceleration $a$ is given by $a = \frac{F}{m}$.Substituting the values: $a = \frac{3}{0.3} = 10 \, m/s^2$.Therefore,the initial acceleration is $10 \, m/s^2$.

$A$ particle of mass $0.3 \, kg$ is subjected to a force $F = -kx$ with $k = 15 \, N/m$. What will be its initial acceleration if it is released from a point $20 \, cm$ away from the origin? (in $m/s^2$)

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