$A$ particle of mass $m$ is moving in a straight line with momentum $p$. Starting at time $t = 0$,a force $F = kt$ acts in the same direction on the moving particle during time interval $T$ so that its momentum changes from $p$ to $3p$. Here $k$ is a constant. The value of $T$ is

  • A
    $2\sqrt{\frac{k}{p}}$
  • B
    $2\sqrt{\frac{p}{k}}$
  • C
    $\sqrt{\frac{2k}{p}}$
  • D
    $\sqrt{\frac{2p}{k}}$

Explore More

Similar Questions

$A$ force $\vec{F_1}$ of magnitude $4 \ N$ acts on an object of mass $1 \ kg$ at the origin in a direction $30^{\circ}$ above the positive $x$-axis. $A$ second force $\vec{F_2}$ of magnitude $4 \ N$ acts on the same object in the direction of the positive $y$-axis. The magnitude of the acceleration of the object is nearly: (in $m \ s^{-2}$)

$A$ body of mass $4 \ kg$ experiences two forces $\overrightarrow{F}_1 = 5 \hat{i} + 8 \hat{j} + 7 \hat{k}$ and $\overrightarrow{F}_2 = 3 \hat{i} - 4 \hat{j} - 3 \hat{k}$. The acceleration acting on the body is :

What is dynamics?

When a body is acted upon by a constant force,then which of the following quantities remains constant?

$A$ force vector applied on a mass is represented as $\vec{F} = 6\hat{i} - 8\hat{j} + 10\hat{k} \, N$ and it accelerates with $1 \, m/s^2$. What will be the mass of the body?

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo