(C) Initial momentum of the system is given by:$\vec{P}_i = mv\hat{i} + mv\hat{j}$Magnitude of initial momentum:$|\vec{P}_i| = \sqrt{(mv)^2 + (mv)^2}

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(C) Initial momentum of the system is given by:$\vec{P}_i = mv\hat{i} + mv\hat{j}$Magnitude of initial momentum:$|\vec{P}_i| = \sqrt{(mv)^2 + (mv)^2} = \sqrt{2}mv$Final momentum of the system after coalescence is:$\vec{P}_f = (2m)\vec{V}$By the law of conservation of linear momentum,$\vec{P}_i = \vec{P}_f$:$\sqrt{2}mv = 2mV$Solving for $V$:$V = \frac{\sqrt{2}mv}{2m} = \frac{v}{\sqrt{2}}$

Class 11 Physics Work, Energy, Power and Collision Perfectly Inelastic Collision

Medium

$A$ particle of mass $m$ moving eastward with a speed $v$ collides with another particle of the same mass moving northward with the same speed $v$. The two particles coalesce on collision. The new particle of mass $2m$ will move in the north-easterly direction with a velocity

A
$v/2$
B
$2v$
C
$v/\sqrt{2}$
D
$v$

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Work, Energy, Power and Collision

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Perfectly Inelastic Collision

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$A$ particle of mass $m$ moving eastward with a speed $v$ collides with another particle of the same mass moving northwards with the same speed $v$. The two particles coalesce on collision. The new particle of mass $2m$ will move with velocity:

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$A$ particle of mass $m$ moving with velocity $v$ collides with a stationary particle of mass $2m$ and sticks to it. What will be the speed of the system?

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$A$ particle of mass $m$ moving eastward with a speed $v$ collides with another particle of the same mass moving northward with the same speed $v$. The two particles coalesce on collision. The new particle of mass $2m$ will move in the north-easterly direction with a velocity

Similar Questions

$A$ particle of mass $m$ moving with velocity $V_0$ strikes a simple pendulum of mass $m$ and sticks to it. The maximum height attained by the pendulum will be

$A$ particle of mass $m_1$ undergoes a perfectly inelastic head-on collision with another particle of mass $m_2$ at rest $(m_2 > m_1)$. What fraction of the initial kinetic energy is converted into heat energy during this collision?

$A$ bag of mass $M$ is suspended by a long string. $A$ bullet of mass $m$ moving with velocity $v$ hits the bag and gets embedded in it. For the (bag + bullet) system:

$A$ particle of mass $m$ moving eastward with a speed $v$ collides with another particle of the same mass moving northwards with the same speed $v$. The two particles coalesce on collision. The new particle of mass $2m$ will move with velocity:

$A$ particle of mass $m$ moving with velocity $v$ collides with a stationary particle of mass $2m$ and sticks to it. What will be the speed of the system?

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