$A$ particle starts from a point $P$ at a distance of $A/2$ from the mean position $O$ and travels towards the left as shown in the figure. If the time period of $SHM$ executed about $O$ is $T$ and the amplitude is $A$,then the equation of motion of the particle is:

  • A
    $x = A \sin \left( \frac{2\pi}{T}t + \frac{\pi}{6} \right)$
  • B
    $x = A \sin \left( \frac{2\pi}{T}t + \frac{5\pi}{6} \right)$
  • C
    $x = A \cos \left( \frac{2\pi}{T}t + \frac{\pi}{6} \right)$
  • D
    $x = A \cos \left( \frac{2\pi}{T}t + \frac{\pi}{3} \right)$

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