A particle with charge +Q and mass m enters a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) When a charged particle enters a perpendicular magnetic field,it follows a circular path. The time period of a full circular orbit is $T = \frac{2

Vedclass · Accepted Answer

$T \left( \frac{\pi - 2	heta}{2\pi} ight)$

Vedclass · Answer

(D) When a charged particle enters a perpendicular magnetic field,it follows a circular path. The time period of a full circular orbit is $T = \frac{2\pi m}{QB}$.From the geometry of the path,the particle enters the field at an angle $	heta$ with the normal to the boundary $YZ$. The angle subtended by the arc of the circular path inside the magnetic field at the center is $\phi = \pi - 2	heta$.The time spent in the magnetic field is given by $t = \frac{\phi}{2\pi} T$.Substituting $\phi = \pi - 2	heta$,we get $t = \frac{\pi - 2	heta}{2\pi} T = T \left( \frac{\pi - 2	heta}{2\pi} ight)$.

$A$ particle with charge $+Q$ and mass $m$ enters a magnetic field of magnitude $B,$ existing only to the right of the boundary $YZ.$ The direction of the motion of the particle is perpendicular to the direction of $B.$ Let $T = 2\pi\frac{m}{QB}.$ The time spent by the particle in the field will be:

Similar Questions

The time period of a charged particle undergoing a circular motion in a uniform magnetic field is independent of its

$A$ deuteron and an alpha particle having equal kinetic energy enter perpendicular into a magnetic field. Let $r_{d}$ and $r_{\alpha}$ be their respective radii of circular path. The value of $\frac{r_{d}}{r_{\alpha}}$ is equal to

In an experiment,electrons are accelerated from rest by applying a voltage of $500 \, V$. Calculate the radius of the path if a magnetic field of $100 \, mT$ is then applied. [Charge of the electron $= 1.6 \times 10^{-19} \, C$,Mass of the electron $= 9.1 \times 10^{-31} \, kg$]

If a proton enters perpendicularly into a magnetic field with velocity $v$,the time period of revolution is $T$. If the proton enters with velocity $2v$,what will be the time period?

$A$ proton of mass $1.67 \times 10^{-27} \, kg$ and charge $1.6 \times 10^{-19} \, C$ is projected with a speed of $2 \times 10^6 \, m/s$ at an angle of $60^\circ$ to the $X$-axis. If a uniform magnetic field of $0.104 \, T$ is applied along the $Y$-axis,the path of the proton is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module