A particular station of All India Radio,New D | vedclass

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Question

(A) The relationship between frequency $(
u)$,wavelength $(\lambda)$,and speed of light $(c)$ is given by the formula: $
u = \frac{c}{\lambda}$.Rear

Vedclass · Accepted Answer

$219.3 \, m$

Vedclass · Answer

(A) The relationship between frequency $(
u)$,wavelength $(\lambda)$,and speed of light $(c)$ is given by the formula: $
u = \frac{c}{\lambda}$.Rearranging the formula to solve for wavelength: $\lambda = \frac{c}{
u}$.Given: $c = 3.0 	imes 10^{8} \, m \, s^{-1}$ and $
u = 1,368 \, kHz = 1,368 	imes 10^{3} \, Hz$.Substituting the values: $\lambda = \frac{3.0 	imes 10^{8} \, m \, s^{-1}}{1,368 	imes 10^{3} \, s^{-1}}$.$\lambda = \frac{300,000,000}{1,368,000} \, m \approx 219.29 \, m$.Rounding to one decimal place,we get $\lambda \approx 219.3 \, m$.

$A$ particular station of All India Radio,New Delhi,broadcasts on a frequency of $1,368 \, kHz$. The wavelength of the electromagnetic radiation emitted by the transmitter is : [speed of light $c = 3.0 \times 10^{8} \, m \, s^{-1}$]

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