(B) The magnitude of acceleration $a$ of a particle performing $SHM$ is given by $|a| = \omega^2 y$,where $\omega$ is the angular frequency and $y$ is

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(B) The magnitude of acceleration $a$ of a particle performing $SHM$ is given by $|a| = \omega^2 y$,where $\omega$ is the angular frequency and $y$ is the displacement from the mean position.Given: $|a| = 20 \; m/s^2$ and $y = 5 \; m$.Substituting these values into the formula: $20 = \omega^2 (5)$.$\omega^2 = 4 \Rightarrow \omega = 2 \; rad/s$.The time period $T$ is given by $T = \frac{2\pi}{\omega}$.$T = \frac{2\pi}{2} = \pi \; s$.

Class 11 Physics Oscillations SHM of Simple Pendulum

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$A$ pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20 \; m/s^2$ at a distance of $5 \; m$ from the mean position. The time period of oscillation is

NEET 2018 All NEET

A
$2\pi \; s$
B
$\pi \; s$
C
$1 \; s$
D
$2 \; s$

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Oscillations

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SHM of Simple Pendulum

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The linear displacement $x$ of the bob of a simple pendulum from its mean position varies as $x = a \sin \left(\frac{\pi}{\sqrt{2}} t\right)$,where $a$ is its amplitude expressed in meters and $t$ is in seconds. The length of the simple pendulum is (Take $g = \pi^{2} \ m/s^{2}$): (in $m$)

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$A$ ball suspended by a thread swings in a vertical plane so that its magnitude of acceleration in the extreme position and lowest position are equal. The angle $(\theta)$ of thread deflection in the extreme position will be :

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$A$ pendulum is suspended in a lift and its period of oscillation when the lift is stationary is $T_0$. What must be the acceleration of the lift for the period of oscillation of the pendulum to be $T_0/2$?

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$A$ pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20 \; m/s^2$ at a distance of $5 \; m$ from the mean position. The time period of oscillation is

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The linear displacement $x$ of the bob of a simple pendulum from its mean position varies as $x = a \sin \left(\frac{\pi}{\sqrt{2}} t\right)$,where $a$ is its amplitude expressed in meters and $t$ is in seconds. The length of the simple pendulum is (Take $g = \pi^{2} \ m/s^{2}$): (in $m$)

$A$ simple pendulum,suspended from the ceiling of a stationary van,has time period $T$. If the van starts moving with a uniform velocity,the period of the pendulum will be

If two persons sit on a swing instead of one,why does the time period not change?

$A$ ball suspended by a thread swings in a vertical plane so that its magnitude of acceleration in the extreme position and lowest position are equal. The angle $(\theta)$ of thread deflection in the extreme position will be :

$A$ pendulum is suspended in a lift and its period of oscillation when the lift is stationary is $T_0$. What must be the acceleration of the lift for the period of oscillation of the pendulum to be $T_0/2$?

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