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(A) During free expansion of a perfect gas,no work is done $(W = 0)$ because the external pressure is zero.Also,no heat is exchanged with the surround

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Remains constant

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(A) During free expansion of a perfect gas,no work is done $(W = 0)$ because the external pressure is zero.Also,no heat is exchanged with the surroundings $(Q = 0)$.According to the first law of thermodynamics,$\Delta U = Q - W$.Since $Q = 0$ and $W = 0$,the change in internal energy $\Delta U = 0$.For a perfect gas,internal energy depends only on temperature $(U \propto T)$.Since internal energy remains constant,the temperature of the gas remains constant.

$A$ perfect gas contained in a cylinder is kept in vacuum. If the cylinder suddenly bursts,then the temperature of the gas

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