$A$ permanent magnet in the shape of a thin cylinder of length $10$ $cm$ has magnetization $M = 10^6$ $A/m$. Calculate the magnetization current $I_M$.

The magnetic moment produced in a substance of $1 \ gm$ is $6 \times 10^{-7} \ A \cdot m^2$. If its density is $5 \ gm/cm^3$,then the intensity of magnetization (in $A/m$) will be:

The magnetic induction and magnetising field intensity in a sample of magnetic material are $B$ and $H$ respectively. The magnetic susceptibility of the material is

$A$ bar magnet having length $5 \ cm$ and area of cross-section $4 \ cm^{2}$ has a magnetic moment of $2 \ Am^{2}$. If the magnetic susceptibility is $5 \times 10^{-6}$,the magnetic intensity will be:

$A$ rod of ferromagnetic material with dimensions $10 \, cm \times 0.5 \, cm \times 0.2 \, cm$ is placed in a magnetic field of strength $0.5 \times 10^4 \, A/m$. As a result,a magnetic moment of $5 \, A \cdot m^2$ is produced in the rod. The value of the total magnetic induction will be (in $Tesla$):

The magnetic susceptibility of the material of a rod is $599$. The absolute permeability of the material of the rod will be $\left[\mu_0=4 \pi \times 10^{-7} \text{ SI unit}\right]$.