A person sells two articles,each for Rs. 1040 | vedclass

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(D) Selling price of each article = $Rs. 1040$.Cost price of the first article $(CP_1)$ = $\frac{1040}{1 - 0.20} = \frac{1040}{0.8} = Rs. 1300$.Cost p

Vedclass · Accepted Answer

$15.5$

Vedclass · Answer

(D) Selling price of each article = $Rs. 1040$.Cost price of the first article $(CP_1)$ = $\frac{1040}{1 - 0.20} = \frac{1040}{0.8} = Rs. 1300$.Cost price of the second article $(CP_2)$ = $\frac{1040}{1 - 0.10} = \frac{1040}{0.9} = Rs. 1155.56$.Total Cost Price = $1300 + 1155.56 = Rs. 2455.56$.Total Selling Price = $1040 + 1040 = Rs. 2080$.Total Loss = $2455.56 - 2080 = Rs. 375.56$.Overall percentage loss = $\left(\frac{375.56}{2455.56}ight) 	imes 100 \approx 15.29\%$. Since this is not among the options,the correct answer is $D$ (None of these).

$A$ person sells two articles,each for $Rs. 1040$. He incurs a $20\%$ loss on the first and a $10\%$ loss on the second. Find the overall percentage loss. (in $\%$)

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