A piece of wire of resistance 4,Omega is bent | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The original wire has a resistance of $R = 4\,\Omega$. When the wire is bent at its mid-point,it is divided into two equal halves,each having a re

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(B) The original wire has a resistance of $R = 4\,\Omega$. When the wire is bent at its mid-point,it is divided into two equal halves,each having a resistance of $R' = \frac{R}{2} = \frac{4}{2} = 2\,\Omega$. When these two halves are twisted together,they form a parallel combination. The equivalent resistance $R_{eq}$ of two resistors in parallel is given by $\frac{1}{R_{eq}} = \frac{1}{R'} + \frac{1}{R'}$. Substituting the values,$\frac{1}{R_{eq}} = \frac{1}{2} + \frac{1}{2} = 1$. Therefore,$R_{eq} = 1\,\Omega$.

$A$ piece of wire of resistance $4\,\Omega$ is bent through $180^o$ at its mid-point and the two halves are twisted together. The new resistance is ............ $\Omega$.

Similar Questions

Three resistances of equal values are arranged in four different configurations as shown below. Power dissipation in the increasing order is

The equivalent resistance across $A$ and $B$ as shown in the figure is ............. $\Omega$.

Two identical heater filaments are connected first in parallel and then in series. At the same applied voltage,the ratio of heat produced in the same time for parallel to series will be:

$A$ heater coil connected to a supply of $220 \ V$ is dissipating some power $P_1$. The coil is cut into half and the two halves are connected in parallel. The heater now dissipates a power $P_2$. The ratio of power $P_1 : P_2$ is

In the given circuit,the equivalent resistance between the points $A$ and $B$ is (in $ohm$):

Vedclass Test Series

Exam Paper Generator

Online Exam Module