$A$ pipe closed at one end produces a fundamental note of $412 \, Hz$. It is cut into two pieces of equal length. The fundamental notes produced by the two pieces are:

When an open pipe is closed from one end,the third overtone of the closed pipe is higher in frequency by $150 \ Hz$ than the second overtone of an open pipe. The fundamental frequency of the open-ended pipe will be (in $Hz$)

In an open organ pipe, $v_3$ and $v_6$ are the $3^{\text{rd}}$ and $6^{\text{th}}$ harmonic frequencies, respectively. If $v_6 - v_3 = 2200 \text{ Hz}$, then the length of the pipe is . . . . . . mm. (Take the velocity of sound in air as $330 \text{ m/s}$.)

If the velocity of sound in air is $350 \ m/s$,then the fundamental frequency of an open organ pipe of length $50 \ cm$ will be ............... $Hz$.

In an organ pipe closed at one end,the sum of the frequencies of the first three overtones is $3930 \ Hz$. The frequency of the fundamental mode of the organ pipe is: (in $Hz$)

The closed and open organ pipes have the same length $L$. When they are vibrating simultaneously in their first overtone,they produce $4$ beats per second. The length of the open pipe is made half $(L/2)$ and that of the closed pipe is made two times $(2L)$ the original. Now,the number of beats produced if the two pipes are vibrating in their fundamental modes simultaneously is: