A plane electromagnetic wave travels in a med | vedclass

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(C) The speed of an electromagnetic wave in a medium is given by $v = \frac{c}{\sqrt{\mu_{r} \epsilon_{r}}}$.Given $\mu_{r} = 1.61$ and $\epsilon_{r}

Vedclass · Accepted Answer

$8.48 \; V m^{-1}$

Vedclass · Answer

(C) The speed of an electromagnetic wave in a medium is given by $v = \frac{c}{\sqrt{\mu_{r} \epsilon_{r}}}$.Given $\mu_{r} = 1.61$ and $\epsilon_{r} = 6.44$,the speed $v = \frac{3 	imes 10^{8}}{\sqrt{1.61 	imes 6.44}} = \frac{3 	imes 10^{8}}{\sqrt{10.3684}} = \frac{3 	imes 10^{8}}{3.22} \approx 9.317 	imes 10^{7} \; m s^{-1}$.The relationship between electric field $E$ and magnetic field $B$ is $E = vB$.Since $B = \mu_{0} \mu_{r} H$,we have $E = v \mu_{0} \mu_{r} H$.$E = (9.317 	imes 10^{7}) 	imes (4 \pi 	imes 10^{-7}) 	imes (1.61) 	imes (4.5 	imes 10^{-2})$.$E = 9.317 	imes 4 	imes 3.1416 	imes 1.61 	imes 4.5 	imes 10^{-2} \approx 8.48 \; V m^{-1}$.

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