A planet orbits the sun in an elliptical path | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Kepler's second law,the angular momentum of the planet about the sun remains constant throughout its orbit.The angular momentum $L$ i

Vedclass · Accepted Answer

$\frac{r_P}{r_A} = \frac{v_A}{v_P}$

Vedclass · Answer

(A) According to Kepler's second law,the angular momentum of the planet about the sun remains constant throughout its orbit.The angular momentum $L$ is given by $L = mvr \sin(	heta)$. At perihelion $(P)$ and aphelion $(A)$,the velocity vector is perpendicular to the position vector,so $	heta = 90^\circ$ and $\sin(90^\circ) = 1$.Thus,the angular momentum at perihelion is $L_P = m v_P r_P$ and at aphelion is $L_A = m v_A r_A$.Since $L_P = L_A$,we have:$m v_P r_P = m v_A r_A$Dividing both sides by $m$ and rearranging the terms,we get:$v_P r_P = v_A r_A$$\frac{r_P}{r_A} = \frac{v_A}{v_P}$

$A$ planet orbits the sun in an elliptical path as shown in the figure. Let $v_P$ and $v_A$ be the speed of the planet when at perihelion and aphelion respectively. Which of the following relations is correct?

Similar Questions

If a planet revolves around the sun with an angular velocity $(\omega)$ and distance $(r)$,then the areal velocity of the planet is proportional to which of the following?

$A$ planet revolves around the sun in an elliptical orbit. The linear speed of the planet will be maximum at

$A$ planet of mass $m$ is moving in an elliptical orbit about the sun with time period $T$. If $A$ is the area of the orbit,then its angular momentum is:

Which of the following orbits is a possible orbit for a planet?

$A$ planet takes $200$ days to complete one revolution around the Sun. If the distance of the planet from the Sun is reduced to one-fourth of the original distance,how many days will it take to complete one revolution?

Vedclass Test Series

Exam Paper Generator

Online Exam Module