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(B) The work done by the electrostatic force is equal to the negative change in the potential energy of the system.$W = -\Delta U = U_i - U_f$Initiall

Vedclass · Accepted Answer

$6q^2 / 4\pi\varepsilon_0 r$

Vedclass · Answer

(B) The work done by the electrostatic force is equal to the negative change in the potential energy of the system.$W = -\Delta U = U_i - U_f$Initially,the central charge $q$ is at a distance $r$ from each of the six charges $q$. The potential energy of the central charge due to the six surrounding charges is $U_i = 6 	imes (kq^2 / r) = 6q^2 / 4\pi\varepsilon_0 r$.When the central charge is moved to infinity,its potential energy becomes $U_f = 0$.Therefore,the work done by the electrostatic force is $W = U_i - U_f = 6q^2 / 4\pi\varepsilon_0 r - 0 = 6q^2 / 4\pi\varepsilon_0 r$.

$A$ point charge $q$ is surrounded symmetrically by six identical charges each of magnitude $q$ at a distance $r$ as shown in the figure. How much work is done by the forces of electrostatic repulsion when the point charge $q$ at the centre is moved to infinity?

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