A point equidistant from the points (2, 0) an | vedclass

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(D) Let the point be $P(x, y)$. The distance from $P$ to $(2, 0)$ is equal to the distance from $P$ to $(0, 2)$.Using the distance formula: $\sqrt{(x-

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$(2, 2)$

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(D) Let the point be $P(x, y)$. The distance from $P$ to $(2, 0)$ is equal to the distance from $P$ to $(0, 2)$.Using the distance formula: $\sqrt{(x-2)^2 + (y-0)^2} = \sqrt{(x-0)^2 + (y-2)^2}$.Squaring both sides: $(x-2)^2 + y^2 = x^2 + (y-2)^2$.Expanding the terms: $x^2 - 4x + 4 + y^2 = x^2 + y^2 - 4y + 4$.Simplifying: $-4x = -4y$,which implies $x = y$.Checking the options,the point $(2, 2)$ satisfies $x = y$ and is equidistant from $(2, 0)$ and $(0, 2)$.

$A$ point equidistant from the points $(2, 0)$ and $(0, 2)$ is

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