A positive charge particle of 100 ,mg is thro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given:Mass $m = 100 \,mg = 100 	imes 10^{-6} \,kg = 10^{-4} \,kg$Electric field $E = 1 	imes 10^{5} \,NC^{-1}$Charge $q = 40 \,\mu C = 40 	imes

Vedclass · Accepted Answer

$0.5$

Vedclass · Answer

(D) Given:Mass $m = 100 \,mg = 100 	imes 10^{-6} \,kg = 10^{-4} \,kg$Electric field $E = 1 	imes 10^{5} \,NC^{-1}$Charge $q = 40 \,\mu C = 40 	imes 10^{-6} \,C$Initial velocity $u = 200 \,ms^{-1}$Final velocity $v = 0 \,ms^{-1}$The force acting on the particle is $F = qE$,which acts in the direction of the field. Since the particle is thrown in the opposite direction,the acceleration $a$ is negative:$a = -\frac{F}{m} = -\frac{qE}{m}$Using the kinematic equation $v^{2} = u^{2} + 2as$,where $v = 0$:$0 = u^{2} - 2 \left( \frac{qE}{m} ight) s$$s = \frac{u^{2}m}{2qE}$Substituting the values:$s = \frac{(200)^{2} 	imes 10^{-4}}{2 	imes 40 	imes 10^{-6} 	imes 10^{5}}$$s = \frac{40000 	imes 10^{-4}}{80 	imes 10^{-1}}$$s = \frac{4}{8} = 0.5 \,m$

Similar Questions

Two metal plates having a potential difference of $800 \; V$ are $0.02 \; m$ apart horizontally. $A$ particle of mass $1.96 \times 10^{-15} \; kg$ is suspended in equilibrium between the plates. If $e$ is the elementary charge,then the charge on the particle is:

$A$ simple pendulum of length $L$ is placed between the plates of a parallel plate capacitor having an electric field $E,$ as shown in the figure. Its bob has mass $m$ and charge $q.$ The time period of the pendulum is given by:

Two charged particles of masses in the ratio $1: 3$ have charges in reciprocal ratio as their masses. They are placed in a uniform electric field and allowed to move. The ratio of their kinetic energies is

$A$ charged particle,initially at rest at $O$,follows the trajectory shown alongside when released. Such a trajectory is possible in the presence of:

$A$ point charge $Q$ is placed in a uniform electric field $\vec{E} = E_1 \hat{i} + E_2 \hat{j}$ at position $(a, b)$. Find the work done in moving it to position $(c, d)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module