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Question

(A) When a charged particle enters a uniform electric field $\vec{E}$ directed along the $y$-axis,it experiences an electric force $\vec{F} = q\vec{E}

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Vertical velocity changes but horizontal velocity remains constant

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(A) When a charged particle enters a uniform electric field $\vec{E}$ directed along the $y$-axis,it experiences an electric force $\vec{F} = q\vec{E}$ in the direction of the $y$-axis.According to Newton's second law,this force causes an acceleration $a_y = \frac{qE}{m}$ in the $y$-direction,which changes the vertical component of the velocity.Since there is no electric field component along the $x$-axis,there is no force acting in the $x$-direction $(F_x = 0)$.Therefore,the horizontal component of the velocity remains constant throughout the motion.Thus,the vertical velocity changes while the horizontal velocity remains constant.

$A$ positively charged particle moving along the $x$-axis with a certain velocity enters a uniform electric field directed along the positive $y$-axis. Its

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