A pressure P- absolute temperature T diagram | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) From the ideal gas equation,we have $PV = \mu RT$.This implies $V = \frac{\mu R T}{P}$,or $V \propto \frac{T}{P}$ (since $\mu$ and $R$ are constan

Vedclass · Accepted Answer

Increased

Vedclass · Answer

(C) From the ideal gas equation,we have $PV = \mu RT$.This implies $V = \frac{\mu R T}{P}$,or $V \propto \frac{T}{P}$ (since $\mu$ and $R$ are constant).For a straight line passing through the origin in a $P-T$ diagram,the slope $\frac{P}{T}$ is constant,which represents an isochoric process (constant volume).However,in the given graph,the line segment $1-2$ does not pass through the origin. Let the equation of the line be $P = mT + c$,where $c > 0$.Then,$\frac{P}{T} = m + \frac{c}{T}$.Since $V \propto \frac{T}{P}$,we have $V \propto \frac{1}{m + \frac{c}{T}}$.As the gas is heated from state $1$ to state $2$,the temperature $T$ increases. As $T$ increases,the term $\frac{c}{T}$ decreases. Consequently,the denominator $(m + \frac{c}{T})$ decreases,which means the volume $V$ increases.

$A$ pressure $P-$ absolute temperature $T$ diagram was obtained when a given mass of gas was heated. During the heating process from state $1$ to state $2$,the volume:

Similar Questions

The locus of the poles of focal chords of the parabola $y^2 = 4ax$ is

The $K_{\alpha}$ $X$-ray emission line of tungsten occurs at $\lambda = 0.021 \, nm$. The energy difference between $K$ and $L$ levels in this atom is about:

$A$ ball is dropped from a height $h$ on a floor of coefficient of restitution $e$. The total distance covered by the ball just before the second hit is

The correct output for the given logic circuit and inputs is:

The $P-V$ diagram of $2\,g$ of $He$ gas for the process $A \to B$ is shown. What is the heat given to the gas (in $,P_0V_0$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module