A prism of refracting angle 60^circ is made w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The refractive index $\mu$ of a prism is given by the formula:$\mu = \frac{\sin \left( \frac{A + \delta_m}{2} \right)}{\sin \left( \frac{A}{2} \ri

Vedclass · Accepted Answer

$1.414$

Vedclass · Answer

(D) The refractive index $\mu$ of a prism is given by the formula:$\mu = \frac{\sin \left( \frac{A + \delta_m}{2} \right)}{\sin \left( \frac{A}{2} \right)}$Given:Refracting angle $A = 60^\circ$Angle of minimum deviation $\delta_m = 30^\circ$Substituting these values into the formula:$\mu = \frac{\sin \left( \frac{60^\circ + 30^\circ}{2} \right)}{\sin \left( \frac{60^\circ}{2} \right)}$$\mu = \frac{\sin(45^\circ)}{\sin(30^\circ)}$Since $\sin(45^\circ) = \frac{1}{\sqrt{2}}$ and $\sin(30^\circ) = \frac{1}{2}$:$\mu = \frac{1/\sqrt{2}}{1/2} = \frac{2}{\sqrt{2}} = \sqrt{2}$$\mu \approx 1.414$

$A$ prism of refracting angle $60^\circ$ is made with a material of refractive index $\mu$. For a certain wavelength of light,the angle of minimum deviation is $30^\circ$. For this wavelength,the value of the refractive index of the material is:

Similar Questions

$A$ ray of light is incident on an equilateral glass prism placed on a horizontal table. For minimum deviation,which of the following is true?

Monochromatic light passes through a prism. Compared to that in air, inside the prism the light's

The refraction through the prisms is as shown. Pick out the wrong statement from the following. Path of the light ray in

The angle of minimum deviation for an incident light ray on an equilateral prism is equal to its refracting angle. The refractive index of its material is

The expected graphical representation of the variation of angle of deviation $\delta$ with angle of incidence $i$ in a prism is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module