$A$ prism of refractive index $1.53$ is placed in water of refractive index $1.33$. If the angle of prism is $60^{\circ}$,the angle of minimum deviation in water will be ........$^{\circ}$ $(\sin 35.1^{\circ} = 0.575)$

For a prism,the angle of the prism is $60^{\circ}$ and the refractive index is $\sqrt{7/3}$. The minimum possible angle of incidence so that the light ray is refracted from the second surface is (in $^{\circ}$)

The principal section of a glass prism is an isosceles triangle $ABC$ with $AB = AC$. The face $AC$ is silvered. $A$ ray of light is incident normally on the face $AB$ and after two reflections, it emerges from the base $BC$ perpendicular to the base. The angle $BAC$ of the prism is: (in $^{\circ}$)

The cross-section of a prism is an equilateral triangle $ABC$ as shown in the figure. The minimum deviation is observed when the angle of incidence is equal to the prism angle. The time taken by light to travel from the midpoint $P$ of $BC$ to $A$ is $..... \times 10^{-10} \, s$. (Given: speed of light in vacuum $= 3 \times 10^8 \, m/s$ and $\cos 30^{\circ} = \frac{\sqrt{3}}{2}$)

The refractive index of glass for red light is $1.520$ and for blue light is $1.525$. Let $D_1$ and $D_2$ be the angles of deviation for red and blue light,respectively,in a prism of this glass. Then:

The refractive index of a glass is $1.520$ for red light and $1.525$ for blue light. Let $D_1$ and $D_2$ be the angles of minimum deviation for red and blue light,respectively,in a prism of this glass. Then,