(D) The horizontal velocity is given as $u_x = 9.8 \; m/s$ and the vertical velocity is $u_y = 19.6 \; m/s$.The time of flight $T$ is given by $T = \f

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(D) The horizontal velocity is given as $u_x = 9.8 \; m/s$ and the vertical velocity is $u_y = 19.6 \; m/s$.The time of flight $T$ is given by $T = \frac{2u_y}{g} = \frac{2 \times 19.6}{9.8} = 4 \; s$.The horizontal range $R$ is given by $R = u_x \times T$.Substituting the values,$R = 9.8 \times 4 = 39.2 \; m$.Alternatively,using the formula $R = \frac{2u_x u_y}{g} = \frac{2 \times 9.8 \times 19.6}{9.8} = 39.2 \; m$.

Class 11 Physics 3-2.Motion in Plane Horizontal Projectile Motion

Medium

$A$ projectile is thrown from a point in a horizontal plane such that the horizontal and vertical velocities are $9.8 \; m/s$ and $19.6 \; m/s$ respectively. It will strike the plane after covering a horizontal distance of ........ $m$.

A
$4.9$
B
$9.8$
C
$19.6$
D
$39.2$

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3-2.Motion in Plane

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Horizontal Projectile Motion

If the instantaneous velocity of a particle projected as shown in the figure is given by $v = a \hat{i} + (b - ct) \hat{j}$,where $a, b$,and $c$ are positive constants,the range on the horizontal plane will be

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At the top of the trajectory of a projectile,the acceleration is

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$A$ projectile is fired at $30^{\circ}$ to the horizontal. The vertical component of its velocity is $80 \; ms^{-1}$. Its time of flight is $T$. What will be the velocity of the projectile at $t = \frac{T}{2}$?

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Two particles are projected from the same point with the same speed $u$ such that they have the same range $R$,but different maximum heights,$h_1$ and $h_2$. Which of the following is correct?

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For a projectile,the ratio of the maximum height reached to the square of the time of flight is:

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$A$ projectile is thrown from a point in a horizontal plane such that the horizontal and vertical velocities are $9.8 \; m/s$ and $19.6 \; m/s$ respectively. It will strike the plane after covering a horizontal distance of ........ $m$.

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If the instantaneous velocity of a particle projected as shown in the figure is given by $v = a \hat{i} + (b - ct) \hat{j}$,where $a, b$,and $c$ are positive constants,the range on the horizontal plane will be

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