$A$ proton moves on a circular path with a constant angular speed. What is the correct relation between its magnetic moment $\vec M$ and angular momentum $\vec L$?

  • A
    $\vec M = - \frac{e\vec L}{2m_p}$
  • B
    $\vec M = \frac{e\vec L}{2m_p}$
  • C
    $\vec M = \left( \frac{2e}{m_p} \right)\vec L$
  • D
    $\vec M = - \left( \frac{2e}{m_p} \right)\vec L$

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