$A$ proton is projected with a velocity $10^7\, m/s$,at right angles to a uniform magnetic field of induction $100\, mT$. The time (in seconds) taken by the proton to traverse a $90^o$ arc is (given $m_p = 1.65 \times 10^{-27}\, kg$ and $q_p = 1.6 \times 10^{-19}\, C$).

  • A
    $0.81 \times 10^{-7}$
  • B
    $1.62 \times 10^{-7}$
  • C
    $2.43 \times 10^{-7}$
  • D
    $3.24 \times 10^{-7}$

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