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Question

(D) For an electromagnetic wave,the relationship between the maximum electric field intensity $(E_0)$ and the maximum magnetic flux density $(B_0)$ is

Vedclass · Accepted Answer

$3.3 	imes 10^{-13} \, T$

Vedclass · Answer

(D) For an electromagnetic wave,the relationship between the maximum electric field intensity $(E_0)$ and the maximum magnetic flux density $(B_0)$ is given by the equation: $B_0 = \frac{E_0}{c}$,where $c$ is the speed of light in vacuum $(c \approx 3 	imes 10^8 \, m/s)$.Given: $E_0 = 10^{-4} \, V/m$.Substituting the values: $B_0 = \frac{10^{-4}}{3 	imes 10^8} \, T$.$B_0 = \frac{1}{3} 	imes 10^{-12} \, T = 0.333 	imes 10^{-12} \, T = 3.33 	imes 10^{-13} \, T$.Therefore,the correct option is $D$.

$A$ radiowave has a maximum electric field intensity of $10^{-4} \, V/m$ on arrival at a receiving antenna. The maximum magnetic flux density of such a wave is:

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