A ray of light incident normally on an isosce | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) From the figure,it is clear that Total Internal Reflection $(TIR)$ takes place at the surfaces $AC$ and $BC$.For $TIR$ to occur,the angle of incid

Vedclass · Accepted Answer

$\sqrt{2}$

Vedclass · Answer

(A) From the figure,it is clear that Total Internal Reflection $(TIR)$ takes place at the surfaces $AC$ and $BC$.For $TIR$ to occur,the angle of incidence $i$ must be greater than the critical angle $C$.Here,the angle of incidence at the surfaces is $45^{\circ}$.Therefore,$45^{\circ} > C$.Taking the sine on both sides,$\sin(45^{\circ}) > \sin(C)$.Since $\sin(C) = \frac{1}{\mu}$,we have $\frac{1}{\sqrt{2}} > \frac{1}{\mu}$.This implies $\mu > \sqrt{2}$.Hence,the least value of the refractive index is $\mu_{least} = \sqrt{2}$.

$A$ ray of light incident normally on an isosceles right-angled prism travels as shown in the figure. The least value of the refractive index of the prism must be

Similar Questions

$A$ beam of light consisting of red,green and blue colours is incident on a right-angled prism. The refractive index of the material of the prism for the above red,green and blue wavelengths are $1.39, 1.44$ and $1.47$ respectively.
The prism will

The critical angle of a medium with respect to air is $45^o$. The refractive index of the medium is

$A$ ray of light refracts from medium $1$ into a thin layer of medium $2$, crosses the layer, and is incident at the critical angle on the interface between medium $2$ and $3$ as shown in the figure. If the angle of incidence of the ray is $\theta$, the value of $\theta$ is

$A$ glass prism of refractive index $1.5$ is immersed in water (refractive index $4/3$) as shown in the figure. $A$ light beam incident normally on face $AB$ undergoes total internal reflection at face $BC$.

$A$ cut diamond sparkles because of its

Vedclass Test Series

Exam Paper Generator

Online Exam Module