A ray of light passes through an equilateral | vedclass

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(D) Given that the prism is equilateral,the angle of the prism $A = 60^o$.According to the problem,the angle of incidence $i$ is equal to the angle of

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$30$

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(D) Given that the prism is equilateral,the angle of the prism $A = 60^o$.According to the problem,the angle of incidence $i$ is equal to the angle of emergence $e$,and both are equal to $3/4$ of the angle of the prism.Thus,$i = e = \frac{3}{4} 	imes 60^o = 45^o$.For a prism,the relationship between the angle of incidence,angle of emergence,angle of the prism,and the angle of deviation $\delta$ is given by the formula: $i + e = A + \delta$.Substituting the known values: $45^o + 45^o = 60^o + \delta$.$90^o = 60^o + \delta$.Therefore,the angle of deviation $\delta = 90^o - 60^o = 30^o$.

$A$ ray of light passes through an equilateral glass prism in such a manner that the angle of incidence is equal to the angle of emergence and each of these angles is equal to $3/4$ of the angle of the prism. The angle of deviation is......$^o$

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