A ray of light strikes a plane mirror M at an | vedclass

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(C) The total deviation $\delta_{net}$ is the sum of the deviation produced by the mirror and the deviation produced by the prism.$1$. Deviation by th

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$92$

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(C) The total deviation $\delta_{net}$ is the sum of the deviation produced by the mirror and the deviation produced by the prism.$1$. Deviation by the mirror: When a ray strikes a mirror at an angle of incidence $i$,the deviation produced is $\delta_{mirror} = 180^o - 2i$.Given $i = 45^o$,$\delta_{mirror} = 180^o - 2(45^o) = 180^o - 90^o = 90^o$.$2$. Deviation by the prism: For a thin prism with a small apex angle $A$,the deviation is $\delta_{prism} = (\mu - 1)A$.Given $\mu = 1.5$ and $A = 4^o$,$\delta_{prism} = (1.5 - 1) 	imes 4^o = 0.5 	imes 4^o = 2^o$.$3$. Total deviation: $\delta_{net} = \delta_{mirror} + \delta_{prism} = 90^o + 2^o = 92^o$.

$A$ ray of light strikes a plane mirror $M$ at an angle of $45^o$ as shown in the figure. After reflection,the ray passes through a prism of refractive index $1.5$ whose apex angle is $4^o$. The total angle through which the ray is deviated is....$^o$

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