(C) For total internal reflection to occur,the angle of incidence $i$ must be greater than the critical angle $C$ $(i > C)$.Given $i = 45^o$,we requir

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(C) For total internal reflection to occur,the angle of incidence $i$ must be greater than the critical angle $C$ $(i > C)$.Given $i = 45^o$,we require $45^o > C$,which implies $\sin 45^o > \sin C$.We know that $\sin C = \frac{1}{\mu}$,so $\sin 45^o > \frac{1}{\mu}$.Substituting $\sin 45^o = \frac{1}{\sqrt{2}}$,we get $\frac{1}{\sqrt{2}} > \frac{1}{\mu}$,which simplifies to $\mu > \sqrt{2}$.Since $\sqrt{2} \approx 1.414$,we need $\mu > 1.414$.Among the given options,only $\mu = 1.5$ satisfies this condition.

Class 12 Physics Ray Optics and Optical Instruments Critical Angle and Total Internal Reflection

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$A$ ray of light travelling in a transparent medium of refractive index $\mu$ falls on a surface separating the medium from air at an angle of incidence of $45^o$. For which of the following values of $\mu$ can the ray undergo total internal reflection?

A
$\mu = 1.33$
B
$\mu = 1.4$
C
$\mu = 1.5$
D
$\mu = 1.25$

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Ray Optics and Optical Instruments

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Critical Angle and Total Internal Reflection

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$A$ ray of light travelling in a transparent medium of refractive index $\mu$ falls on a surface separating the medium from air at an angle of incidence of $45^o$. For which of the following values of $\mu$ can the ray undergo total internal reflection?

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$A$ ray of laser of a wavelength $630 \, nm$ is incident at an angle of $30^{\circ}$ at the diamond-air interface. It is going from diamond to air. The refractive index of diamond is $2.42$ and that of air is $1$. Choose the correct option.

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