A ray of light travels from an optically dens | vedclass

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Question

(C) When a ray of light travels from a denser to a rarer medium,the deviation $\delta$ is given by $\delta = \phi - 	heta$,where $\phi$ is the angle

Vedclass · Accepted Answer

$\pi - 2C$

Vedclass · Answer

(C) When a ray of light travels from a denser to a rarer medium,the deviation $\delta$ is given by $\delta = \phi - 	heta$,where $\phi$ is the angle of refraction and $	heta$ is the angle of incidence.For refraction,the maximum deviation occurs when $	heta = C$ and $\phi = \frac{\pi}{2}$. In this case,$\delta_{refraction} = \frac{\pi}{2} - C$.When total internal reflection occurs,the angle of incidence $	heta$ is greater than or equal to $C$. The deviation is $\delta = \pi - 2	heta$. The deviation is maximum when $	heta$ is minimum,i.e.,$	heta = C$. Thus,$\delta_{reflection} = \pi - 2C$.Comparing the two cases,since $\pi - 2C > \frac{\pi}{2} - C$ (as $C < \frac{\pi}{2}$),the maximum possible deviation is $\pi - 2C$.

$A$ ray of light travels from an optically denser to a rarer medium. The critical angle for the two media is $C$. The maximum possible deviation of the ray will be

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