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Question

(C) The total deviation $\delta$ produced by two plane mirrors inclined at an angle $	heta$ is given by $\delta = 360^o - 2	heta$.Given $\delta = 27

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$7$

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(C) The total deviation $\delta$ produced by two plane mirrors inclined at an angle $	heta$ is given by $\delta = 360^o - 2	heta$.Given $\delta = 270^o$,we have $270^o = 360^o - 2	heta$.$2	heta = 360^o - 270^o = 90^o$,so $	heta = 45^o$.The number of images $n$ formed by two mirrors inclined at an angle $	heta$ is given by $n = \frac{360^o}{	heta} - 1$.Substituting $	heta = 45^o$,we get $n = \frac{360^o}{45^o} - 1 = 8 - 1 = 7$.Therefore,the number of observable images is $7$.

$A$ ray reflected successively from two plane mirrors inclined at a certain angle undergoes a deviation of $270^o$ after two reflections. The number of images observable is:

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