$A$ reaction rate constant is given by $k = 1.2 \times 10^{14} \, e^{-25000/RT} \, sec^{-1}$. It means

• A
  $\log \, k$ versus $\log \, T$ will give a straight line with a slope as $25000$
• B
  $\log \, k$ versus $\log \, T$ will give a straight line with a slope as $-2500$
• C
  $\log \, k$ versus $\log \, T$ will give a straight line with a slope as $-25000$
• D
  $\log \, k$ versus $1/T$ will give a straight line