A real gas behaves like an ideal gas if its | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) real gas obeys the van der Waals equation:$(P + \frac{an^2}{V^2})(V - nb) = nRT$At high temperature,the kinetic energy of gas molecules is very la

Vedclass · Accepted Answer

pressure is low and temperature is high

Vedclass · Answer

(D) real gas obeys the van der Waals equation:$(P + \frac{an^2}{V^2})(V - nb) = nRT$At high temperature,the kinetic energy of gas molecules is very large,making the intermolecular forces of attraction negligible.At low pressure,the volume of the gas is very large,making the volume occupied by the gas molecules $(nb)$ negligible compared to the total volume $(V)$.Under these conditions (high temperature and low pressure),the van der Waals equation simplifies to the ideal gas equation: $PV = nRT$.Therefore,a real gas behaves like an ideal gas at low pressure and high temperature.

$A$ real gas behaves like an ideal gas if its

Similar Questions

According to the Kinetic Theory of Gases,which of the following statements is correct?

The value of $C_p - C_v = 1.00 R$ for a gas in state $A$ and $C_p - C_v = 1.06 R$ in another state $B$. If $P_A$ and $P_B$ denote the pressure and $T_A$ and $T_B$ denote the temperature in the two states,then:

Under what conditions does a real gas obey the relation $PV = RT$?

$A$ real gas behaves as an ideal gas at

The diameter of an oxygen molecule is $2.94 \times 10^{-10} \ m$. The van der Waals gas constant '$b$' in $m^3/mol$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module