A rectangular sheet of area 264 text{ cm}^2 a | vedclass

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(A) Given: Area of the rectangular sheet $= 264 	ext{ cm}^2$,Width $= 11 	ext{ cm}$.Length of the sheet $= \frac{	ext{Area}}{	ext{Width}} = \frac{

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$231$

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(A) Given: Area of the rectangular sheet $= 264 	ext{ cm}^2$,Width $= 11 	ext{ cm}$.Length of the sheet $= \frac{	ext{Area}}{	ext{Width}} = \frac{264}{11} = 24 	ext{ cm}$.When the sheet is rolled along its breadth,the width of the sheet becomes the circumference of the base of the cylinder,and the length of the sheet becomes the height of the cylinder.Circumference $= 2\pi r = 11 	ext{ cm}$.$r = \frac{11}{2\pi} = \frac{11 	imes 7}{2 	imes 22} = \frac{7}{4} 	ext{ cm}$.Height $(h) = 24 	ext{ cm}$.Volume of the cylinder $= \pi r^2 h = \frac{22}{7} 	imes (\frac{7}{4})^2 	imes 24$.Volume $= \frac{22}{7} 	imes \frac{49}{16} 	imes 24 = 22 	imes \frac{7}{16} 	imes 24 = 22 	imes 7 	imes 1.5 = 231 	ext{ cm}^3$.

$A$ rectangular sheet of area $264 \text{ cm}^2$ and width $11 \text{ cm}$ is rolled along its breadth to make a hollow cylinder. The volume of the cylinder is (in $\text{cm}^3$):

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