A red coloured mixed oxide (X) on treatment w | vedclass

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(B) The red coloured mixed oxide $(X)$ is $Pb_3O_4$ (red lead).When $Pb_3O_4$ reacts with conc. $HNO_3$,it forms lead$(II)$ nitrate and lead$(IV)$ oxi

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$Pb_3O_4, PbO_2, PbCl_2$

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(B) The red coloured mixed oxide $(X)$ is $Pb_3O_4$ (red lead).When $Pb_3O_4$ reacts with conc. $HNO_3$,it forms lead$(II)$ nitrate and lead$(IV)$ oxide $(PbO_2)$,which is compound $(Y)$:$Pb_3O_4 + 4HNO_3 \rightarrow 2Pb(NO_3)_2 + PbO_2 + 2H_2O$$PbO_2$ (compound $Y$) reacts with $HCl$ to produce lead$(II)$ chloride $(PbCl_2)$,which is compound $(Z)$:$PbO_2 + 4HCl \rightarrow PbCl_2 + Cl_2 + 2H_2O$$Pb_3O_4$ (compound $X$) also reacts with conc. $HCl$ to produce $PbCl_2$ (compound $Z$):$Pb_3O_4 + 8HCl \rightarrow 3PbCl_2 + Cl_2 + 4H_2O$Thus,$(X), (Y),$ and $(Z)$ are $Pb_3O_4, PbO_2,$ and $PbCl_2$ respectively.

Column-$I$	Column-$II$
$(i)$ Solvay process	$(p)$ $Na_2O$
$(ii)$ Evolve $CO_2$ on heating	$(q)$ $Na_2O_2$
$(iii)$ Aqueous solution is not neutral towards litmus	$(r)$ $NaHCO_3$
$(iv)$ Used as air purifier in submarine	$(s)$ $Na_2CO_3$

$A$ red coloured mixed oxide $(X)$ on treatment with conc. $HNO_3$ gives a compound $(Y).$ $(Y)$ with $HCl$ produces a chloride compound $(Z)$ which can also be produced by treating $(X)$ with conc. $HCl.$ Compounds $(X),$ $(Y),$ and $(Z)$ will be

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Write a note on $s$-block elements of the periodic table.

Assertion : $Al(OH)_3$ is insoluble in $NH_4OH$ but soluble in $NaOH$.
Reason : $NaOH$ is a strong alkali.

Match the following columns:

Column-$I$ Column-$II$

$(i)$ Solvay process $(p)$ $Na_2O$

$(ii)$ Evolve $CO_2$ on heating $(q)$ $Na_2O_2$

$(iii)$ Aqueous solution is not neutral towards litmus $(r)$ $NaHCO_3$

$(iv)$ Used as air purifier in submarine $(s)$ $Na_2CO_3$

To distinguish between $A$ and $B$,it is observed that both elements form oxides,but $B$ also forms a nitride when burnt in air. What are $A$ and $B$?

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