A resistance of 300 Omega and an inductance | vedclass

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Question

(A) In an $LR$ series circuit,the phase angle $\phi$ between the voltage and current is given by the formula: $	an \phi = \frac{X_L}{R}$.Here,$R = 30

Vedclass · Accepted Answer

$	an^{-1} \frac{4}{3}$

Vedclass · Answer

(A) In an $LR$ series circuit,the phase angle $\phi$ between the voltage and current is given by the formula: $	an \phi = \frac{X_L}{R}$.Here,$R = 300 \ \Omega$,$L = \frac{1}{\pi} \ H$,and frequency $f = 200 \ Hz$.The inductive reactance $X_L$ is calculated as: $X_L = 2\pi f L = 2\pi 	imes 200 	imes \frac{1}{\pi} = 400 \ \Omega$.Substituting the values into the phase angle formula:$	an \phi = \frac{400}{300} = \frac{4}{3}$.Therefore,the phase angle is $\phi = 	an^{-1} \left( \frac{4}{3} ight)$.

$A$ resistance of $300 \ \Omega$ and an inductance of $\frac{1}{\pi} \ H$ are connected in series to an $AC$ voltage of $20 \ V$ and $200 \ Hz$ frequency. The phase angle between the voltage and current is

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