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(D) To find the minimum selling price,we must identify the scheme that offers the maximum total discount.$I.$ Equivalent discount $= 10 + 10 - \frac{1

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$IV$

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(D) To find the minimum selling price,we must identify the scheme that offers the maximum total discount.$I.$ Equivalent discount $= 10 + 10 - \frac{10 	imes 10}{100} = 20 - 1 = 19 \%$$II.$ Equivalent discount $= 12 + 8 - \frac{12 	imes 8}{100} = 20 - 0.96 = 19.04 \%$$III.$ Equivalent discount $= 15 + 5 - \frac{15 	imes 5}{100} = 20 - 0.75 = 19.25 \%$$IV.$ Equivalent discount $= 20 \%$Comparing the discounts: $19 \% Since scheme $IV$ offers the highest discount of $20 \%$,the selling price will be the minimum under scheme $IV$.

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