A right circular cylinder has a mass m,radius | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The forces acting on the cylinder are the gravitational force $(mg)$ acting downwards and the buoyant force $(F_b)$ acting upwards.According to Ar

Vedclass · Accepted Answer

$|\pi r^2 \rho gh - mg|$

Vedclass · Answer

(D) The forces acting on the cylinder are the gravitational force $(mg)$ acting downwards and the buoyant force $(F_b)$ acting upwards.According to Archimedes' principle,the buoyant force is equal to the weight of the fluid displaced by the cylinder.The volume of the cylinder is $V = \pi r^2 h$.Therefore,the buoyant force is $F_b = \rho Vg = \rho (\pi r^2 h) g = \pi r^2 \rho gh$.The net force $F_{net}$ on the cylinder is the difference between the buoyant force and the gravitational force.$F_{net} = F_b - mg = \pi r^2 \rho gh - mg$.Since we are asked for the magnitude of the net force,we take the absolute value:$|F_{net}| = |\pi r^2 \rho gh - mg|$.

$A$ right circular cylinder has a mass $m$,radius $r$,and a height $h$. The cylinder is completely submerged in a fluid of density $\rho$,as shown in the diagram,and is released. What is the magnitude of the net force on the cylinder initially?

Similar Questions

$A$ body floats in water with $40 \%$ of its volume outside water. When the same body floats in oil, $60 \%$ of its volume remains outside oil. The relative density of the oil is

When does a body float on the surface of a liquid?

$A$ body floats in water with $40 \%$ of its volume outside water. When the same body floats in an oil, $60 \%$ of its volume remains outside oil. The relative density of oil is

$A$ body floats with $\frac{1}{n}$ of its volume outside of water. If the body is pushed to a depth $h$ inside the water and released, it will come to the surface after time $t$. Then:

State and prove Archimedes' principle.

Vedclass Test Series

Exam Paper Generator

Online Exam Module