(C) The average kinetic energy $(K.E.)$ of an ideal gas atom is given by the formula: $K.E. = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant

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(C) The average kinetic energy $(K.E.)$ of an ideal gas atom is given by the formula: $K.E. = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant and $T$ is the absolute temperature in Kelvin.From this relation,it is clear that $K.E. \propto T$.Given that the initial temperature $T_1 = 300\, K$ and the final temperature $T_2 = 600\, K$.Since the temperature is doubled $(T_2 = 2 T_1)$,the average kinetic energy will also be doubled.

Class 11 Physics Kinetic Theory of Gases Pressure and Energy

Easy

$A$ sealed container with negligible coefficient of volumetric expansion contains helium (a monoatomic gas). When it is heated from $300\, K$ to $600\, K,$ the average kinetic energy $(K.E.)$ of helium atoms is

A
Halved
B
Unchanged
C
Doubled
D
Increased by factor $\sqrt{2}$

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Kinetic Theory of Gases

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Pressure and Energy

In the kinetic theory of gases,a molecule of mass $m$ of an ideal gas collides with a wall of a vessel with velocity $V$. The change in the linear momentum of the molecule is

MediumAIIMS 1997

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The average translational kinetic energy of ${O_2}$ (molar mass $32$) molecules at a particular temperature is $0.048 \; eV$. The translational kinetic energy of ${N_2}$ (molar mass $28$) molecules in $eV$ at the same temperature is:

EasyIIT 1997

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$A$ gas is filled in a container at pressure ${P_0}$. If the mass of all molecules is halved and their $rms$ speed is doubled,what will be the new pressure?

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According to the kinetic theory of gases,the average kinetic energy of $1$ gram-mole of a gas is given by which of the following expressions?

Medium

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Absolute zero temperature is the temperature at which:

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$A$ sealed container with negligible coefficient of volumetric expansion contains helium (a monoatomic gas). When it is heated from $300\, K$ to $600\, K,$ the average kinetic energy $(K.E.)$ of helium atoms is

Similar Questions

In the kinetic theory of gases,a molecule of mass $m$ of an ideal gas collides with a wall of a vessel with velocity $V$. The change in the linear momentum of the molecule is

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$A$ gas is filled in a container at pressure ${P_0}$. If the mass of all molecules is halved and their $rms$ speed is doubled,what will be the new pressure?

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