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(B) In simple harmonic motion $(SHM)$,the velocity of the object is given by $v = \omega \sqrt{A^2 - x^2}$,where $A$ is the amplitude and $x$ is the d

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either $1$ or $5$

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(B) In simple harmonic motion $(SHM)$,the velocity of the object is given by $v = \omega \sqrt{A^2 - x^2}$,where $A$ is the amplitude and $x$ is the displacement from the mean position.At the extreme positions $(x = \pm A)$,the velocity $v$ is zero.Since the target spends more time in the regions where its speed is minimum (near the extreme positions),the probability of the gun hitting the target is highest in these regions.In the given figure,regions $1$ and $5$ correspond to the extreme positions of the oscillation.Therefore,the player should aim at either region $1$ or region $5$ to maximize the number of hits.

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