A short-sighted person can see distinctly onl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) short-sighted person (myopic) cannot see objects beyond their far point clearly.Here,the far point of the person is $d = 100\, cm = 1\, m$.To see

Vedclass · Accepted Answer

$- 1.0\, D$

Vedclass · Answer

(B) short-sighted person (myopic) cannot see objects beyond their far point clearly.Here,the far point of the person is $d = 100\, cm = 1\, m$.To see a distant object (at infinity),the lens must form a virtual image of the object at the person's far point.Using the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.Here,$u = \infty$ and $v = -100\, cm = -1\, m$ (since the image must be formed on the same side as the object).$\frac{1}{f} = \frac{1}{-1} - \frac{1}{\infty} = -1 - 0 = -1\, m^{-1}$.Power $P = \frac{1}{f} = -1\, D$.

$A$ short-sighted person can see distinctly only those objects which lie between $10\, cm$ and $100\, cm$ from him. The power of the spectacle lens required to see a distant object is

Similar Questions

$A$ man can see only between $75 \, cm$ and $100 \, cm$. The power of the lens required to correct the near point will be:

When the human eye is focused on an object,the ciliary muscles are least strained when the object is at:

The image formed on the retina of the eye is proportional to:

$A$ person has a near point of $50 \, cm$ and a far point of $3 \, m$. What power of lens is required to $(i)$ read and $(ii)$ see distant stars?

The near point and far point of a normal human eye are respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module