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(B) The time period of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{l}{g_{eff}}}$,where $l$ is the length of the pendulum and $g_{e

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$T_2 = T_1$

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(B) The time period of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{l}{g_{eff}}}$,where $l$ is the length of the pendulum and $g_{eff}$ is the effective acceleration due to gravity.In the first case,the lift is stationary,so $g_{eff} = g$. Thus,$T_1 = 2\pi \sqrt{\frac{l}{g}}$.In the second case,the lift moves downward with a constant velocity. Since the velocity is constant,the acceleration of the lift is zero $(a = 0)$.Therefore,the effective acceleration remains $g_{eff} = g - a = g - 0 = g$.Since $g_{eff}$ is the same in both cases,the time period remains the same,i.e.,$T_2 = T_1$.

$A$ simple pendulum hanging from the ceiling of a stationary lift has a time period $T_1$. When the lift moves downward with constant velocity,the time period is $T_2$,then

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