A simple pendulum is set up in a trolley whic | vedclass

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(B) In the accelerated frame of reference (the trolley),a fictitious force (pseudo force) $F_p = ma$ acts on the bob of the pendulum in the direction

Vedclass · Accepted Answer

$	an^{-1}(\frac{a}{g})$ in the backward direction

Vedclass · Answer

(B) In the accelerated frame of reference (the trolley),a fictitious force (pseudo force) $F_p = ma$ acts on the bob of the pendulum in the direction opposite to the acceleration of the trolley.The forces acting on the bob in the frame of the trolley are:$1$. Gravitational force $mg$ acting vertically downwards.$2$. Pseudo force $ma$ acting horizontally backwards.$3$. Tension $T$ in the string.In the equilibrium position (mean position),the net force on the bob is zero. Resolving the forces,we have:$	an 	heta = \frac{	ext{Pseudo force}}{	ext{Gravitational force}} = \frac{ma}{mg} = \frac{a}{g}$Therefore,$	heta = 	an^{-1}(\frac{a}{g})$ in the backward direction.

$A$ simple pendulum is set up in a trolley which moves to the right with an acceleration $a$ on a horizontal plane. Then the thread of the pendulum in the mean position makes an angle $\theta$ with the vertical.

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