(B) At point $A$ (or $C$),the bob is at its maximum height $H$ relative to point $B$,so its kinetic energy is zero and potential energy is $mgH$.At po

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(B) At point $A$ (or $C$),the bob is at its maximum height $H$ relative to point $B$,so its kinetic energy is zero and potential energy is $mgH$.At point $B$,the bob is at its lowest position,so its potential energy is zero and all energy is converted into kinetic energy.According to the law of conservation of mechanical energy:$PE_{A} + KE_{A} = PE_{B} + KE_{B}$$mgH + 0 = 0 + \frac{1}{2}mv^2$$mgH = \frac{1}{2}mv^2$$v^2 = 2gH$$v = \sqrt{2gH}$

Class 11 Physics Oscillations SHM of Simple Pendulum

Medium

$A$ simple pendulum with a bob of mass $m$ oscillates from $A$ to $C$ and back to $A$ such that $PB$ is $H$. If the acceleration due to gravity is $g$,then the velocity of the bob as it passes through $B$ is

AIPMT 1995 All AIPMT

A
$mgH$
B
$\sqrt{2gH}$
C
$\sqrt{gH}$
D
Zero

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Oscillations

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SHM of Simple Pendulum

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$A$ simple pendulum with a bob of mass $m$ oscillates from $A$ to $C$ and back to $A$ such that $PB$ is $H$. If the acceleration due to gravity is $g$,then the velocity of the bob as it passes through $B$ is

Similar Questions

If the temperature of a pendulum with time period $T$ is increased by $\Delta \theta$,the change in the time period of the pendulum is .......

If the length of a clock pendulum increases by $0.2 \%$ due to atmospheric temperature rise,then the loss in time of the clock per day is ........... $s$.

$A$ simple pendulum is vibrating in an evacuated chamber. It will oscillate with:

Two pendulums of length $1.21 \,m$ and $1.0 \,m$ start vibrating. At some instant,the two are in the mean position in the same phase. After how many vibrations of the longer pendulum will the two be in phase again?

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