A small child tries to move a large rubber to | vedclass

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Question

(A) Since the toy is in equilibrium (it does not move),the net force acting on it must be zero.The forces acting on the toy are:$1$. The pushing force

Vedclass · Accepted Answer

the resultant of the pushing force $F$,weight of the toy,normal force by the ground on the toy and the frictional force is zero

Vedclass · Answer

(A) Since the toy is in equilibrium (it does not move),the net force acting on it must be zero.The forces acting on the toy are:$1$. The pushing force $F$ applied by the child.$2$. The weight of the toy $(W = mg)$ acting downwards.$3$. The normal force $(N)$ exerted by the ground acting upwards.$4$. The frictional force $(f)$ exerted by the ground acting horizontally to oppose the motion.According to Newton's first law,for an object in equilibrium,the vector sum of all external forces acting on it must be zero.Therefore,$\vec{F} + \vec{W} + \vec{N} + \vec{f} = 0$.This means the resultant of these four forces is zero.Option $(a)$ is correct.

$A$ small child tries to move a large rubber toy placed on the ground. The toy does not move but gets deformed under her pushing force $F$,which is obliquely upward as shown in the figure. Then,

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