A solid cone of height 24 , cm and base radiu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The volume of the solid cone is given by $V_{cone} = \frac{1}{3} \pi r_1^2 h_1 = \frac{1}{3} 	imes \pi 	imes 8^2 	imes 24 = 512 \pi \, cm^3$.Th

Vedclass · Accepted Answer

$57.8$

Vedclass · Answer

(C) The volume of the solid cone is given by $V_{cone} = \frac{1}{3} \pi r_1^2 h_1 = \frac{1}{3} 	imes \pi 	imes 8^2 	imes 24 = 512 \pi \, cm^3$.The volume of the solid cylinder formed is $V_{cylinder} = \pi r_2^2 h_2 = \pi 	imes 6^2 	imes 6 = 216 \pi \, cm^3$.The volume of material wasted is $V_{wasted} = V_{cone} - V_{cylinder} = 512 \pi - 216 \pi = 296 \pi \, cm^3$.The percentage of material wasted is $\frac{V_{wasted}}{V_{cone}} 	imes 100 = \frac{296 \pi}{512 \pi} 	imes 100 = \frac{296}{512} 	imes 100 = 57.8125 \% \approx 57.8 \%$.

$A$ solid cone of height $24 \, cm$ and base radius $8 \, cm$ is melted to form a solid cylinder of radius $6 \, cm$ and height $6 \, cm$. In the whole process,what percent of material is wasted (in $\%$)?

Similar Questions

Three solid spheres have their radii $r_{1}, r_{2}$ and $r_{3}$. The spheres are melted to form a single solid sphere of a bigger radius. The radius of the new sphere is:

The volumes of a right circular cylinder and a sphere are equal. The radius of the cylinder and the diameter of the sphere are equal. The ratio of the height to the radius of the cylinder is:

The perpendicular height of a conical tent is $4 \frac{2}{3} \text{ m}$ and the diameter of its base is $6 \text{ m}$. If $11$ persons can sleep in this tent,find how many average cubic meters $(m^3)$ of air each person gets?

The length of a room is $12\, m$,width $8\, m$,and height $6\, m$. How many boxes will it hold if each box occupies $1.5\, m^3$ of space?

$A$ school room is to be built to accommodate $70$ children,so as to allow $2.2\, m^2$ of floor area and $11\, m^3$ of space for each child. If the room is $14\, m$ long,what must be its breadth and height?

Vedclass Test Series

Exam Paper Generator

Online Exam Module