A solid cone of height 36 , cm and radius of | vedclass

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(A) Volume of the cone $V_1 = \frac{1}{3} \pi r_1^2 h_1 = \frac{1}{3} \pi (9)^2 (36) = \frac{1}{3} \pi (81) (36) = 972 \pi \, cm^3$.Volume of the cyli

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(A) Volume of the cone $V_1 = \frac{1}{3} \pi r_1^2 h_1 = \frac{1}{3} \pi (9)^2 (36) = \frac{1}{3} \pi (81) (36) = 972 \pi \, cm^3$.Volume of the cylinder $V_2 = \pi r_2^2 h_2 = \pi (9)^2 (9) = 729 \pi \, cm^3$.Volume of material wasted $= V_1 - V_2 = 972 \pi - 729 \pi = 243 \pi \, cm^3$.Percentage of material wasted $= \left( \frac{	ext{Volume wasted}}{	ext{Original volume}} ight) 	imes 100 = \left( \frac{243 \pi}{972 \pi} ight) 	imes 100$.$= \frac{1}{4} 	imes 100 = 25 \%$.

$A$ solid cone of height $36 \, cm$ and radius of base $9 \, cm$ is melted to form a solid cylinder of radius $9 \, cm$ and height $9 \, cm$. What percent of material is wasted in this process (in $\%$)?

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